Mathematics
09.03.2021 01:49
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Your english teacher has decided to randomly assign poems for the class to read.

Your english teacher has decided to randomly assign poems for the class to read. the syllabus includes 2 poems by shakespeare, 3 poems by coleridge, 5 poems by tennyson, and 4 poems by lord byron. what is the probability that you will be assigned a poem by coleridge and then a poem by lord byron?
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bobxspam
bobxspam
4,8(12 marks)
|\Omega|=14\cdot13=182\\
|A|=3\cdot4=12\\\\
P(A)=\dfrac{12}{182}=\dfrac{6}{91}
sabon
sabon
5,0(91 marks)

1. 46% patients are dogs.

2. standard error is 0.726636085.

3. margin of error 90% confidence interval is 1.19531636.

4. margin of error 95% confidence interval is 1.424206727.

step-by-step explanation:

total number of patients is 50.

total number of dogs is

7+4+5+5+2=23

1.   percentage of patients that were dogs

    \frac{23}{50}\times 100=46\%

2.   the formula of standard deviation is

    \sigma^2=\frac{\sum(x-\overline{x})^2}{n}

    \sigma=\sqrt{\frac{13.2}{5}}

    \sigma=\sqrt{2.64}

    \sigma=1.624807681

    the formula of standard error is

      s.e.=\frac{\sigma}{\sqrt{n}}

    where, σ is standard deviation and n is sample size.

      s.e.=\frac{1.624807681}{\sqrt{5}}

      s.e.=0.726636085

3.   the formula of marginal error is

    m.e.=z\times s.e.

    where, z is the value for desired level of confidence.

    the value of z at 90% confidence interval is 1.645.

    m.e.=1.645\times 0.726636085

    m.e.=1.19531636

4.   the value of z at 95% confidence interval is 1.96.

      m.e.=1.96\times 0.726636085

      m.e.=1.424206727

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