Chemistry
16.06.2020 12:17
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. You see sunlight shining onto green grass. Make a claim about how reflection,

. You see sunlight shining onto green grass. Make a claim about how reflection, refraction, transmission, and absorption affect the color of the grass and explain your reasoning.
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sam710
sam710
4,5(8 marks)

Great question!The color of grass leaves (usually green) is mostly due to the absorbance of the other wavelengths of visible light by chlorophyll. Therefore, any differences in gene expression (that ultimately determine phenotype) that affect the concentration of chlorophyll in the leaf will, in turn, affect the color of that leaf. My guess is that, in the absence of light, you could still measure chlorophyll concentration, and assume what the color would be. However, you need transmitted (reflected) light in order to perceive color. I don't know, if a tree falls in the forest, and none is around to hear it, does it make a sound? Hope this helps. Keep the questions coming!

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Dweath50
Dweath50
4,9(89 marks)

Use molecular geometries. Some geometries are asymmetrical, so they necessarily are polar. Other molecules are symmetrical, so even though they contain elements of great differences in electronegativities, these molecules are non-polar.

Consider carbon dioxide - which has the elements carbon and oxygen in its composition. The EN of carbon is 2.5; the EN of oxygen is 3.5. Clearly, there is a big difference in electronegativity, which suggests that the oxygens are isolating electron density away from the carbon.

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As we can see in the above picture, the two permanent dipoles cancel each other out since they are equal in magnitude and opposite in direction. So carbon dioxide might have elements of great difference in EN, but is still non-polar.

Now apply this knowledge to your problem. To determine molecular geometries, understand that both electrons and attached atoms influence geometry. Try looking up and applying the AXE method. I will leave my answer at here for now, since you have not shown much work in tackling this problem.

Explanation:

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