You have 25 cm^3 of a gas at 25 C and 103.86 kappa. What is the new volume at STP?

23.5cm^3

Explanation:

From the question given, we obtained the following data:

V1 = 25 cm^3

T1 = 25°C = 25 + 273 = 298K

P1 = 103.86 kPa = 103860Pa

V2 =?

T2 = at stp = 273K

P2 = at stp = 101325Pa

Using the general gas equation to solve for the new volume we obtain:

P1V1/T1 = P2V2/T2

(103860x25)/298 = 101325xV2 /273

298x101325xV2 = 103860x25x273

Divide both side by 298x101325

V2 = (103860x25x273) /(298x101325)

V2 = 23.5cm^3

it will form an a compund

Explanation:

Potassium chlorate on strong heating decomposes to the chloride and oxygen gas. The decomposition is faster in the presence of MnO2 as catalyst (Standard method of preparation of oxygen in the laboratory).