You drop a batitin a stationary elevator and the ball hits the floor in o 50 s.

Time taken to hit the floor, t = 0.61 s

Option a.

Given:

t = 0.50 s

Solution:

Initial velocity of the ball when dropped, u = 0 m/s

Now, using second equation of motion when acceleration due to gravity acts:

h = 1.225 m

Now, when the lift moves in the upward direction with a constant speed of 1.0 m/s, u = - 1.0 m/s

Time taken by the ball to hit the floor travelling a distance h = 1.225 m is given by:

Now,

Solving the above quadratic equation, we get:

t = 0.612 s  = 0.61 s