Time taken to hit the floor, t = 0.61 s
Option a.
Given:
t = 0.50 s
Solution:
Initial velocity of the ball when dropped, u = 0 m/s
Now, using second equation of motion when acceleration due to gravity acts:
h = 1.225 m
Now, when the lift moves in the upward direction with a constant speed of 1.0 m/s, u = - 1.0 m/s
Time taken by the ball to hit the floor travelling a distance h = 1.225 m is given by:
Now,
Solving the above quadratic equation, we get:
t = 0.612 s = 0.61 s