Mathematics
30.09.2021 23:51
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X-3 and x-1/3 are factors of ax^2+5x+b,show that a=-3/2

X-3 and x-1/3 are factors of ax^2+5x+b,show that a=-3/2
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terencehouse
terencehouse
4,6(62 marks)
Hello,

ax^2+5x+b=a(x^2+ \frac{5}{a}*x+ \frac{b}{a})\\
=k(x-3)(x- \frac{1}{3})\\
=k(x^2-3x- \frac{1}{3}*x+1)\\
=k(x^2- \frac{10}{3}*x+1)\\

x^2--\ \textgreater \  k=a\\
x--\ \textgreater \ 5=-a* \frac{10}{3} ==\ \textgreater \ a=- \frac{3}{2} \\

x^0--\ \textgreater \ b=a
1xXJOKERXx3
1xXJOKERXx3
4,9(63 marks)

Distributive property, Inverse Operation, and Division property of Equality

Step-by-step explanation:

Because 8•x is 8x and 8x3 is 24 so then the equation would be 8x-24=-40 then you have to add 24 on both sides to the 8x by itself and also get -16 which you would divide 8 on both sides to get x= -2

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