Mathematics
03.10.2020 09:02
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Write the following phrase as a variable expression. use x to represent a number

Write the following phrase as a variable expression. use x to represent "a number". the sum of a number and four the translation is
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bellamparker
bellamparker
5,0(57 marks)
Sum means add, a number means x, and four means, uh, 4...

x+4. is what you're looking for
valenzueladomipay09u
valenzueladomipay09u
4,8(14 marks)

correct answer is option 3:

\dfrac{x^{2} }{30}+\dfrac{y^{2} }{5}=1

Step-by-step explanation:

Given that

Ellipse passes through coordinates:

\approx (5\dfrac{1}{2},0),\approx  (-5\dfrac{1}{2},0), \approx  (0,2)\ and\ \approx (0,-2)

Points inside ellipse (5, 0) and (-5,0).

Given the options:

1.\ \dfrac{x^{2} }{5}+\dfrac{y^{2} }{30}=1\\2.\ \dfrac{x^{2} }{5}-\dfrac{y^{2} }{30}=1\\3.\ \dfrac{x^{2} }{30}+\dfrac{y^{2} }{5}=1\\4.\ \dfrac{x^{2} }{30}+\dfrac{y^{2} }{25}=1\\

Let us try to put the coordinates in the options and check which equation gets satisfied.

Putting x = 0, and trying to find out y in option 1.

\ \dfrac{0^{2} }{5}+\dfrac{y^{2} }{30}=1\\\Rightarrow \dfrac{y^{2} }{30}=1\\\Rightarrow y =\pm\sqrt{30} \approx \pm5\dfrac{1}{2}

But, the points are \approx (5\dfrac{1}{2},0),\approx  (-5\dfrac{1}{2},0), \approx  (0,2)\ and\ \approx (0,-2)

So, option (1) is false.

Putting x = 0 to find y in option 2.

\ \dfrac{0^{2} }{5}-\dfrac{y^{2} }{30}=1\\\Rightarrow \dfrac{y^{2} }{30}=-1

y will have imaginary values so ellipse not possible at x = 0.

So, option (2) is false.

Putting x = 0 to find y in option 3.

\ \dfrac{0^{2} }{30}+\dfrac{y^{2} }{5}=1\\\Rightarrow \dfrac{y^{2} }{5}=1\\\Rightarrow y \approx \pm2

Putting y = 0 to find y in option 3.

\ \dfrac{x^{2} }{30}+\dfrac{0^{2} }{5}=1\\\Rightarrow \dfrac{x^{2} }{30}=1\\\Rightarrow x \approx \pm5\dfrac{1}{2}

So, the points \approx (5\dfrac{1}{2},0),\approx  (-5\dfrac{1}{2},0), \approx  (0,2)\ and\ \approx (0,-2) are satisfied.

Putting (5, 0) and (-5,0) in LHS of option 3:

\ \dfrac{(\pm5)^{2} }{30}+\dfrac{0 }{5}\\\Rightarrow \dfrac{25} {30}\\\Rightarrow \dfrac{5}{6}

i.e. both the points are inside ellipse.

Hence correct answer is option 3:

\dfrac{x^{2} }{30}+\dfrac{y^{2} }{5}=1


Which of the following is the equation for the graph shown?

graph of an ellipse on a coordinate pla

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