Mathematics
15.08.2020 00:59
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Write the equation of the circle whose center is (-4,8) and has a diameter of 18

Write the equation of the circle whose center is (-4,8) and has a diameter of 18
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akp24
akp24
4,7(44 marks)

(x + 4)^2 + (y - 8)^2 = 81

or

(x + 4)^2 + (y - 8)^2 = 9^2 depending on how your teacher wants it written.

Step-by-step explanation:

The standard form for a circle is

(x + h)^2 + (y + k)^2 = r^2

r is the radius.

You are given the diameter

r = d/2

r = 18/2

r = 9

So you already have the right hand side of the equation

(x + h)^2 + (y + k)^2 = 9*2

(x + h)^2 + (y + k)^2 = 81

You basically have h and k as well. They come from the center point.

h = 4

k = - 8

So the equation of the circle (and the answer) is

(x + 4)^2 + (y - 8)^2 = 81

One question remains. Why do the x and y values change signs? If you know what the distance formula is, then what you are finding is the distance r of all points on the circle from the center of the circle.

It is the distance formula that is actually the formula for the circle.

Symonek
Symonek
4,5(30 marks)

y=1

Step-by-step explanation:

The correct table that shows the direct variation is:

5      6      y        9

15    18      3       27

Since this is a direct variation, there is a proportional relation.

Therefore:  \frac{27-15}{9-5}=\frac{3-15}{y-5}

This implies that:

\frac{12}{4}=\frac{-12}{y-5}

3=\frac{-12}{y-5}

y-5=\frac{-12}{3}

y-5=-4

y=5-4=1

Therefore the value of y is 1

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