Mathematics
14.07.2021 23:08
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Write an equation of the line that passes through 9, 6 and is perpendicular to the

Write an equation of the line that passes through 9, 6 and is perpendicular to the line whose equation is y equals -1 over 3 x + 7
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amberosekemble8463
amberosekemble8463
4,5(48 marks)
If the line that goes through (9, 6) is perpendicular to y = -1/3x + 7, then their slopes will be opposite reciprocals.  The slope of the line given is -1/3.  The opposite reciprocal of -1/3 is +3.  If we have our new line passing through point with x coordinate 9 and y coordinate 6, we will use that x and y and the slope of 3 to solve the slope-intercept equation for b.  Like this:  9 = 3(6) + b.  9 = 18 + b and b = -9.  That means that the new equation, the one that is perpendicular to the given line, is y = 3x - 9. 
Travisbennington
Travisbennington
4,6(30 marks)

-3

Step-by-step explanation:

2/5(-10x+5)+8x=3(2x+6)-10

-20/5x+10/5+8x=6x+18-10

-4x+2+8x=6x+8

-4x+8x=6x+8-2

4x=6x+6

4x-6x=6

-2x=6

x=6/-2

x=-3

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