Mathematics
28.05.2023 16:57
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With algebra 2: 1. 2.
With algebra 2: 1. [tex]\frac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }[/tex]
2.[tex]3\sqrt[4]{(x-2)^3} -4=20[/tex]
![With algebra 2: 1. [tex]\frac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }[/tex] 2.[tex]3\sqrt[4]{(x-2)^3}](/tpl/images/00/29/5V8BvEuGIGxekO4I.jpg)
![With algebra 2: 1. [tex]\frac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }[/tex] 2.[tex]3\sqrt[4]{(x-2)^3}](/tpl/images/00/29/lz6eUc8jDekYSl3Q.jpg)
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2.[tex]3\sqrt[4]{(x-2)^3} -4=20[/tex]
vitanoeymailcom705
4,8(87 marks)
See explanation
Step-by-step explanation:
1. Given the expression
![\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }](/tpl/images/0481/1637/199ef.png)
Note that
![\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}](/tpl/images/0481/1637/03ad7.png)
When dividing ![\sqrt[7]{x^5}](/tpl/images/0481/1637/3571f.png)
by ![\sqrt[4]{x^2},](/tpl/images/0481/1637/6622f.png)
we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so
and the result is ![x^{\frac{3}{14}}=\sqrt[14]{x^3}](/tpl/images/0481/1637/9a826.png)
2. Given equation ![3\sqrt[4]{(x-2)^3} -4=20](/tpl/images/0481/1637/1289d.png)
Add 4:
![3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24](/tpl/images/0481/1637/73709.png)
Divide by 3:
![\sqrt[4]{(x-2)^3} =8](/tpl/images/0481/1637/7f81a.png)
Rewrite the equation as:
Hence,
christingle2004
4,8(13 marks)
i believe its c
Step-by-step explanation:
hope this helps!
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