Which of the following graphs is not a function? * what are the next 3 terms in
what are the next 3 terms in the sequence? -5, -15, -25, -35, … *
1 point
a) 34, 44, 54
b) - 46, - 56, - 66
c) - 45, - 55, - 65
d) 44, 54, 64
what is the 30th term in a sequence given by the explicit function: a(n) = -1 + (n-1)2 *
1 point
a) 63
b) -57
c) -1
d) 57
11) fill in the blank. the line test is used to determine if a graph is a function. *
1 point
a) vertical
b) linear
c) horizontal
d) algebra
given that f (x) = 3x – 5 and the domain of f is {2,4,6}, find the range of f(x). *
1 point
a) {11,17,20}
b) {-6,-4,-2}
c) {2,4,6}
d) {1,7,13}
16) the set of ordered pairs shown represents a function f. { (4, -2), (-1, -1), (0, 0), (1, -1), (4,2) } select the ordered pair that could be added to the set so that f remains a function.
-45,-55,-65
A(30) = -1 + (30 - 1) * 2 = -1 + 29 * 2 = -1 + 58 = 57 <==
the vertical line test
range is { 1,7,13 }
I am having a problem with the last onewith the points that are listed, it is not a function...because u have 2 x- values that are 4
Ans1: Heart shaped graph
Ans2: option:C
Ans3: option:D
Ans4: option:A
Ans5: option:D
Step-by-step explanation:
Ans1: Heart shaped graph is not a function.
" since for a graph to be a function: any line passing through the domain and parallel to the co-domain should intersect the graph exactly once ".
also we can see from some examples in a figure attached to the answer.
Ans2: we are given a sequence as: -5,-15,-25,-35
as the given sequence is an Arithmetic Progression(A.P.) with a common difference 
Hence the next three terms of the sequence are: -45,-55,-65
Ans3: we are asked to find the 30th term of a sequence
Hence, the 30th term of the given sequence is 57.
Ans4: The vertical line test is used to determine if the graph is a function.
Ans5: we are given a function f(x)=3x-5
with domain={2,4,6}
range of f(x):
when x=2 f(x)=3×2-5=6-5=1
when x=4 f(x)=3×4-5=12-5=7
when x=6 f(x)=3×6-5=18-5=13
Hence, range of f(x)={1,7,13}.
Ans6: the given set of ordered pair is: {(4,-2),(-1,-1),(0,0),(1,-1),(4,2)}
As from the given set we could see that '4' has two images.
As '4' is mapped to '-2' and '2'{ since, the given ordered pair is (4,-2) and(4,2)}
Hence, f can't be a function.
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