The correct answer is 0.9 Liters.
Explanation:
Based on the given reaction:
2NaOH (aq) + H₂SO₄ (aq) ⇒ Na₂SO₄ (aq) + 2H₂O (l)
It is clearly evident from the reaction that one mole of sulfuric acid reacts with two moles of sodium hydroxide. So, 1.8 moles of H₂SO₄ will react with,
2/1 × 1.8 mol = 3.6 moles of NaOH
The molarity or M of NaOH given is 4.0 M, the moles of NaOH given is 3.6. Now the volume of NaOH can be determined by using the formula,
Molarity = no of moles/volume in Liters
4.0 = 3.6/V
V = 3.6/4.0 = 0.9 L
Hence, 0.9 Liters of 4.0 M NaOH will react with 1.8 moles of H₂SO₄.