Engineering
26.11.2022 07:21
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When a measured cell voltage is negative, the electrode to which the red lead is

When a measured cell voltage is negative, the electrode to which the red lead is attached is actually the anode rather than the cathode (i.e., you should enter a positive voltage). The anode is the electrode at which oxidation takes place, so it is surrendering electrons to the external circuit. For the two cells involving the iron and copper species, the Cu(II)/Cu(s) couple is the anode. Which of the following half-cell reactions is taking place at the Cu electrode in the anode compartment of these two cells?
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paigejohnson6161
paigejohnson6161
4,4(28 marks)

C++ program is explained below

Explanation:

#include <iostream>

#include <cmath>

#include <iomanip>

#include <string>

using namespace std;

int main(){

string shape;

double height;

double width;

 double radius;

const double PI = 3.1416;

double length;

cout << "Enter the shape type: (rectangle, circle, cylinder) ";

cin >> shape;

cout << endl;

if (shape == "rectangle"){

 cout << "Enter the length of the rectangle: ";

cin >> length;

cout << endl;

cout << "Enter the width of the rectangle: ";

cin >> width;

cout << endl;

cout << "Perimeter of the rectangle = "<< 2 * (length + width) << endl;

cout << "Area of the rectangle = "<< length * width << endl;

}

else if (shape == "circle"){

 cout << "Enter the radius of the circle: ";

 cin >> radius;

cout << "Area of the circle = "<< PI * pow(radius, 2.0) << endl;

 cout << "Circumference of the circle: "<< 2 * PI * radius << endl;

 cout << endl;

}

else if (shape == "cylinder")

{

cout << "Enter the height of the cylinder: ";

cin >> height;

cout << endl;

cout << "Enter the radius of the base of the cylinder: ";

cin >> radius;

cout << endl;

cout << "Surface area of the cylinder: " << 2 * PI * radius * height + 2 * PI * pow(radius, 2.0)<< endl;

cout << "Volume of the cylinder = "<< PI * pow(radius, 2.0)* height << endl;

}

else

cout << "The program does not handle " << shape << endl;

cout << fixed << showpoint << setprecision(2);

return 0;

}

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