What would be the magnitude of a star with a temperature of 25,000 located on the

A) You would have to run 72.6 m.

B) You would have to run at a final speed of 11.8 m/s or 42.5 km/h.

C) No.

Explanation:

Hi there!

The equations for an object moving in a straight line with constant acceleration are as follows:

x = x0 + v0 * t + 1/2 a * t²

v = v0 + a * t

where

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

If the movement is with constant velocity, the same equations apply only that a = 0.

A) You will catch the bus when your position is the same as the position of the bus.

The equation of your position will be:

x = x0 + v0 * t + 1/2 a * t²    

Since the center of the reference system is located at the point where you start running, x0 = 0. The initial velocity is 0 because you start from rest. Then:

x = 1/2 a * t²

The position of the bus will be:

x = x0 + v * t

Since you start running when the bus is 11.0 m past you, the initial position of the bus is 11.0 m.

If you catch the bus, then:

your position = position of the bus

1/2 a * t² = x0 + v * t

1/2 * 0.960 m/s² * t² = 11.0 m + 5.00 m/s * t

0.48 m/s² * t² - 5.00 m/s * t - 11.0 m

Solving the quadratic equation:

t = 12.3 s

Using t = 12.3 in the equation of your position, we will obtain the distance you have to run to catch the bus:

x = 1/2 * 0.960 m/s² * (12.3 s)² = 72.6 m

B) The equation for velocity is:

v = v0 + a * t

Since you start from rest, v0 = 0. Then, the velocity when you reach the bus at t = 12.3 s will be:

v = a * t

v = 0.960 m/s² * 12.3 s = 11.8 m/s

C) The velocity you have to run is almost the world record of Usain Bolt (45 km / h).

11.8 m/s *(3600 s/ h) *( 1 km / 1000 m) = 42.5 km/h.

Then, no, an average college student would not be able to run that fast.