What volume (in L) of a 2.46 M. magnessium nitrate (Mg(NO3)2) solution would be

0.0847L

Explanation:

The following data were obtained from the question:

C1 = 2.46 M

V1 =?

C2 = 0.758 M

V2 = 275 mL = 275/1000 = 0.275L

Using the dilution formula C1V1 = C2V2, we can confidently calculate the volume of the original solution as follows:

C1V1 = C2V2

2.46 x V1 = 0.758 x 0.275

Divide both side by 2.46

V1 = (0.758 x 0.275) /2.46

V1 = 0.0847L

Therefore, 0.0847L is needed

Speed = v = 3×10⁸ m/s

Wavelength = λ = 5.8×10⁻⁷ m

Frequency = f  

v = fλ

Hence,

f = v/λ

f = 3×10⁸ / 5.8×10⁻⁷

f = 0.517×10⁸⁺⁷

f = 5.17×10¹⁴ Hz                                                                                                                                  

i hope this will help but if im wrong then it will be 5.16x10¹⁴