Chemistry
18.06.2021 03:59
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What ratio is used to carry out each conversion? a.mol ch4 to grams ch4 b.l ch4(g)

What ratio is used to carry out each conversion? a.mol ch4 to grams ch4 b.l ch4(g) to mol ch4(g)(at stp) c.molecules ch4 to mol ch4 i honestly don't kno what it's asking me i got 1 mol ch4/ 16(g) ch4 for a. 1 mol/22.4 l for b. and 6.02 x 10^23 molecules/1 mol but i don't think this is right, is it?
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Dolphin56
Dolphin56
4,8(63 marks)

Explanation:

According to mole concept

a. CH_4Moles to CH_4grams

Number of moles =\frac{\text{Mass of the compound}}{\text{Molar mass of the compound}}

Mass of CH_4= Moles of CH_4\times 16 g/mol

b.CH_4 Liters to CH_4 moles at STP.

At STP,1 mol gas occupies 22.4 L of volume.

Multiply the given volume of gas in L with \frac{1 }{22.4 } moles

c.Molecules CH_4of to moles CH_4

1 mole = N_A=6.022\times 10^{23} atoms or molecules

So, in 1 molecule =\frac{1}{N_A}=\frac{1}{6.022\times 10^{23}} mole.

Multiply the given number of molecules with \frac{1}{6.022\times 10^{23}} mole to get the number of moles of CH_4.

lowkstahyna
lowkstahyna
4,9(26 marks)

0.36 atm is the correct answer.

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