What is the temperature change of 1.0 mol of a monotomic gas if its thermal energy

0.08K

Explanation:

When temperature changes, the corresponding change in thermal energy of a gas is given by:

ΔE (thermal) = 3/2nRΔT

Defining the parameters:

ΔE (thermal) = Increase in thermal energy of the mono atomic gas = 1.0J

n = number of moles of the gas = 1.0mol

R = Ideal gas constant = 8.314J/mol/K

ΔT = change in temperature. This is what we need to find.

Rearranging the equation to make ΔT subject of the formula,

ΔT= 2 x ΔE (thermal) / (3 x n x R)

Therefore, ΔT = 2 x 1.0J / (3 x 1.0mol x 8.314J/mol/K)

ΔT = 2.0J / 24.942J/K

ΔT = 0.0802K

ΔT = 0.08K

The temperature change of 1.0mol of a monoatomic gas if its thermal energy is increased by 1.0J is 0.08K.

Responder:

20.3 ° C

Explicación:

Según la ley de Charles: cuando la presión sobre una muestra de gas seco se mantiene constante, la temperatura y el volumen estarán en proporción directa.

Paso uno:

datos dados

Temperatura T1 = 20 ° C

Temperatura T2 =?

Volumen V1 = 12.2 cm ^ 3

Volumen V2 = 12.4 cm ^ 3

Aplicar la relación temperatura y volumen

sustituyendo tenemos

Cruz multiplicar tenemos

Temperatura delle braci 20.3°C