What is the solution to the system of equations x = y + 4 2x - 3y = -2

x = 14 and y = 10

Step-by-step explanation: What we have in the question is a pair of simultaneous equations as follows(

x = y + 4 ———(1)

2x - 3y = -2 ——(2)

Looking at both equations, one of the variables has a coefficient of 1, and as a result of that, we shall use the substitution method.

From equation (1), x = y + 4

Substitute for the value of x in equation (2)

2x - 3y = -2

2(y + 4) - 3y = -2

2y + 8 -3y = -2

-y + 8 = -2

Subtract 8 from both sides of the equation

-y +8 -8 = -2 -8

-y = -10

Divide both sides of the equation by -1

y = 10

Having calculated y, substitute for the value of y into equation (1)

x = y + 4

x = 10 + 4

x = 14

Therefore, x = 14 and y = 10

The equation of the circle =

x² + y² + 6x - 4y + 9 = 0

Step-by-step explanation: