What is the probability that the die shows an odd number or a number less than 3

So we're first assuming that it's a standard die, one with only six sides.

Now, we can first look at the statement, odd number.

There are three possibilities for this.

1, 3, and 5.

Now for, less than 3.

Two possible numbers.

1, and 2.

So the possible numbers that would satisfy these conditions would be, 

1, 2, 3, and 5.

So 4 numbers.

Since there are 6 total possibilities, the fraction would be 4/6, or 2/3.

So the probability is 2/3.

Second spot will be at (-9, -3)

Step-by-step explanation:

I am searching a buried object by making the center of a field as (0, 0) as origin.

We know on the all the distances on y-axis towards North and East directions will be positive and distances towards West and South will be negative.

Now at point A(-12, 8) I find nothing so I tried a likely looking spot at 3 yards to the east and 11 yards to the south of the first spot.

Therefore, the new spot will be at

For x - coordinates

-12 + 3 = -9 towards east

For y - coordinates

8 - 11 = -3 towards south

New looking like spot will be at (-15, -3)