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What is the mole fraction of calcium chloride in 3.35 m CaCl2(aq)? The molar mass

What is the mole fraction of calcium chloride in 3.35 m CaCl2(aq)? The molar mass of CaCl2 is 111.0 g/mol and the molar mass of water is 18.02 g/mol.
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levicorey846
levicorey846
5,0(57 marks)

The mole fraction of calcium chloride and water in the solution is 0.057 and 0.943 respectively

Explanation:

We are given:

Molality of calcium chloride = 3.35 m

This means that 3.35 moles of calcium chloride are present in 1 kg or 1000 g of water

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of water = 1000 g

Molar mass of water = 18.02 g/mol

Putting values in above equation, we get:

\text{Moles of water}=\frac{1000g}{18.02g/mol}=55.49mol

Total moles of solution = [3.35 + 55.49] = 58.84 moles

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

For calcium chloride:

\chi_{CaCl_2}=\frac{n_{CaCl_2}}{n_{CaCl_2}+n_{H_2O}}\\\\\chi_{CaCl_2}=\frac{3.35}{58.84}=0.057

For water:

\chi_{H_2O}=\frac{n_{H_2O}}{n_{CaCl_2}+n_{H_2O}}\\\\\chi_{H_2O}=\frac{55.49}{58.84}=0.943

Hence, the mole fraction of calcium chloride and water in the solution is 0.057 and 0.943 respectively

gstevens
gstevens
4,9(33 marks)

Explanation:

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