What is the distance between two charges of +7.8 Cand +9.2 C, if they exert a force

required distance is 233.35 m

Explanation:

Given the data in the question;

Sound intensity = 1.62 × 10⁻⁶ W/m²

distance r = 165 m

at what distance from the explosion is the sound intensity half this value?

we know that;

Sound intensity is proportional to 1/(distance)²

i.e

∝ 1/r²

Now, let r² be the distance where sound intensity is half, i.e ₂ = ₁/2

Hence,

₂/₁ = r₁²/r₂²

1/2 = (165)²/ r₂²

r₂² = 2 × (165)²

r₂² = 2 × 27225

r₂² = 54450

r₂ = √54450

r₂ = 233.35 m

Therefore, required distance is 233.35 m