What is latent heat of fusion ...

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Physics: What is latent heat of fusion ...

ebigham5117 · Accepted Answer

This year Venus was slim crescent in March when the Earth-Venus was about L=42*10^6 km

(the minimum distance)
To find its angular diameter we apply the trigonometry
$\tan \alpha = D/L$
where D=21000 km is the planet diameter and L is the distance to the planet. For small angles we consider
$\tan \alpha \approx \alpha$
Thus the angular diameter of venus when it was slim crescent was
$\alpha =D/L =21000/(42*10^6) =2.9*10^{-4} rad$
In degrees this is
$\beta =\alpha*180/\pi = 0.0167 degree$
We know that 3600 seconds correspond to 1 degree. Therefore
$1''=1/3600 =2.8*10^{-4} degree$
Hence
$\beta = 0.0167/2.8*10^{-4} =60.12''
$
Therefore the angular diameter of Venus when it was slim crescent was 60''.

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