There are three sequential operations (Station 1, Satiation 2, and Station 3) in

1 hour 19 mins

Explanation:

The computation of the  theoretical flow time is shown below;

The sequence of operation  represent as a Station 1 -> Station 2 -> Station 3

Now

The capacity of each station is

= number of resources × capacity of each resource

Particulars           Station 1         Station 2         Station 3

resources               1                      2                    3

the capacity of

each resource        3                      5                     5

the capacity of

each station           3                       20                  15

Now The theoretical flow time for each station is  

Station 1 = 60 ÷ (3 ÷ 1) = 20 mins

Station 2 = 60 ÷ (5 ÷ 2) = 24 mins

Station 3 = 60 ÷ (5 ÷ 3) = 35.92 mins

So,

Total theoretical flow time is

= 20 + 24 + 35.92

= 79.92 mins

= 1 hour 19 mins

Explanation:

b. Even-cent method

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