The dimension of the smallest area of the poster is 8 cm by 12 cm
Let the dimensions of the poster be x and y.
So, the area is:
The area is given as 96 cm^2.
So, we have:
The print area is represented as:
Make x the subject in
Substitute 96/y for x in
Express as:
Expand
Differentiate
Set to 0
Add 4 to both sides
Multiply both sides by y^2
Divide both sides by 4
Take square roots
Rewrite as:
Recall that:
So, we have:
Hence, the dimension of the smallest area of the poster is 8 cm by 12 cm
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Therefore the dimension of the poster is 12 cm by 8 cm.
Step-by-step explanation:
Let the length of the poster be x and the width be y.
Given that the area of the poster is 96 cm².
∴xy =96
The sides margins each are 2 cm and the top and bottom margins of the poster are each 3 cm.
The length of printing space is =(x- 2.3) cm
= (x-6) cm
The width of the printing space is =(y-2.2) cm
=( y-4 )cm
The area of the printing space is A=(x-6)(y-4) cm²
∴A=(x-6)(y-4)
[ Putting ]
Differentiating with respect to x
Again differentiating with respect to x
To find the minimum area, we set A'=0
Dimension can't be negative.
Therefore x=12
If x=12, the value of A''>0,then at x=12, the area of the poster will be minimum.
If x=12, the value of A''<0,then at x=12, the area of the poster will be minimum.
Therefore at x= 12 cm the area of the poster will be maximum.
The width of the poster is = 8 cm
Therefore the dimension of the poster is 12 cm by 8 cm.