The sum of three numbers is 50. one number is 10 more than the second number it’s

X + y + z = 50
y  + 10 = x, solving for y, y = x - 10
x = 2z, solving for z, z = x/2
Substituting for y and z,

x + x - 10 + x/2 = 50
(5/2)x - 10 = 50
(5/2)x = 60
x = (2/5) * 60 = 24
y = x - 10 = 24 - 10 = 14
Z = x/2 = 24/2 = 12

Checking:
x + y + z = 50, 24 + 14 + 12 = 50, 50 = 50. Solution meets the initial constraint. 

if u get a f it will bracing it around the C or D range

Step-by-step explanation: