the path of a toy rocket is modelled by the equation y=-x^2+6x+2, where x is the

The path of a toy rocket is defined by the relation y=-3x^2+11x+4, where x is the horizontal distance, in meters, traveled and y is the height, in metres, above the ground.

Determine the zeros of the relation.

-3x^2 + 11x + 4 = 0

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3x^2 - 11x -4 = 0

Factor:

3x^2 - 12x + x - 4 = 0

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3x(x-4) + x-4 = 0

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(x-4)(3x+1) = 0

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x = 4 or x = -1/3

f(x) = -3x^2+11x+4

How far has the rocket traveled horizontally when it lands on the ground?

4 ft.

What is the maximum height of the rocket above the ground, to the nearest hundredth of a meter?

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max occurs when x = -b/2a = -11/(2*-3) = 11/6

height = f(11/6) = 14.083 ft

n= 26, so the answer would be 'B'.

Step-by-step explanation:

n-8=18

n=18+8

n=26