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The critical resolved shear stress for a metal is 31 MPa. Determine the maximum

The critical resolved shear stress for a metal is 31 MPa. Determine the maximum possible yield strength (in MPa) for a single crystal of this metal that is pulled in tension.
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nallwly
nallwly
5,0(84 marks)

62 MPa

Explanation:

We are given that

Critical resolved shear stress for a metal,\tau_{crit}=31MPa

We have to find the maximum possible yield strength for a single crystal of this metal that is pulled in tension.

Yield strength,\sigma_{yield}=\frac{\tau_{crit}}{cos\phi cos\gamma}

Minimum stress is necessary to introduce yielding  when \phi=\gamma=45^{\circ}

\sigma_{yield}=\frac{\tau_{crit}}{cos45cos 45}=2\tau_{crit}

Substitute the values

\sigma_{yield}=2\times 31=62 MPa

Hence, the maximum possible yield strength for a single crystal of this metal that is pulled in tension=62 MPa

jgnjanjdknsjrr9358
jgnjanjdknsjrr9358
4,9(88 marks)
I think You should break it down to the First and third One because of
See the question attached and pleaaa  god will bless youu
See the question attached and pleaaa  god will bless youu

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