F= 69.97 N
Explanation:
Given that
θ = 30°
Horizontal component of the force (F) = 60.6 N
Lets take force exerted on the suitcase= F
The horizontal component = F cosθ
Given that
F cosθ= 60.6 N
F cos 30°= 60.6 N
We know that cos 30° = 0.866
F x 0.866 = 60.6 N
F= 69.97 N
Therefore the force on the suitcase will be 69.97 N