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Suppose 41.9% of Americans are satisfied with their phone service/provider. Random
Suppose 41.9% of Americans are satisfied with their phone service/provider. Random samples of 90 Americans are asked if they are satisfied with their phone service/provider. We record the proportion of respondents who are satisfied.
If we are curious in finding out the probability that less than 41% of respondents in our sample are satisfied, we need to calculate a Z-score. What is the Z-score? (Don't find the probability)
Round your answer to 2 decimal places.
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4(2+3c)=56
8+12c=56
-8 -8
12c=48
/12 /12
c=4