Square both sides
β(2x+1)=2+β(x-3)
or, 2x+1=(2+β(x-3))Β²
solving it you'll get two values of x, which are,
x = 4 and x = 12
(1) 30 + 22i
Step-by-step explanation:
x = 3 + 7i β 2x = 6 + 14i
y = - 6 - 2i β 4y = - 24 - 8i
2x - 8y = ( 6 + 14i ) - ( - 24 - 8i ) = 6 + 14i + 24 + 8i = (6 + 24) + (14i + 8i )
2x - 8y = 30 + 22i