Mathematics
13.09.2020 13:55
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Since cos(x) is the derivative of sin(x), then integral 16 sin^2(x) cos(x) dx can

Since cos(x) is the derivative of sin(x), then integral 16 sin^2(x) cos(x) dx can be done by substituting u = sin (x) sin (x) and du = cos (x) cos (x)^dx. With the substitution u = sin(x), we get integral 16 sin^2 (x) cos(x) dx = 16 integral u^2 du. which integrates to + C. Substituting back in to get the answer in terms of sin(x), we have integral 16 sin^2 (x) cos (x) dx = + C.
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raniacakes
raniacakes
5,0(1 marks)

Complete

Find the integral of  f(x) =  16sin^2 (x ) cos(x) dx

The solution is    \frac{16}{3} sin^{3}x + c

Step-by-step explanation:

So

   Let \  u  =  sin(x)

=>  \frac{du}{dx}  =  cos (x)

=>   du  =  cos(x)dx

So

   \int\limits {16sin^2 (x ) cos(x) dx} \, \equiv \int\limits {16u^2  du}

=>  \int\limits {16u^2  du} = 16 [\frac{u^3}{3} ] + c

Now substituting sin(x) for u  

      \frac{16}{3} u^3 + c  =  \frac{16}{3} sin^{3}x + c

So the  integral of  f(x) =  16sin^2 (x ) cos(x) dx  is

      \frac{16}{3} sin^{3}x + c

okokalyssa
okokalyssa
4,5(95 marks)

6h+4  -2h +3

Step-by-step explanation:

(6h + 4) - (2h - 3)

Distribute

6h+4  -2h +3

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