Mathematics
28.03.2020 11:35
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Show that the curve y = 4 x 3 + 7 x − 5 y=4x3+7x-5 has no tangent line with slope

Show that the curve y = 4 x 3 + 7 x − 5 y=4x3+7x-5 has no tangent line with slope 2 2. y = 4 x 3 + 7 x − 5 ⇒ m = y ' = y=4x3+7x-5⇒m=y′= Preview , but x 2 x2 0 0 for all x x, so m ≥ m≥ for all x x.
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laza87
laza87
4,8(20 marks)

The statement is true (see Step-by-step explanation).

Step-by-step explanation:

The slope of the tangent line for all point of the curve is determine by derive the expression abovementioned in the statement:

y' = 12 \cdot x^{2} + 7

The previous expression represents a parabola, whose output will be positive for all x due to the symmetry of x^{2} and the positive coefficients of the polynomial. If the function is evaluated at x = 0, where the minimum occurs, it is evident that the smallest value is y' = 7 . Therefore, the inexistence of any tangent line with slope 2 associated with that curve is true.

simreg5230
simreg5230
5,0(19 marks)

y=-5/4x+1/4

Step-by-step explanation:

This should help. Remember, God loves you.

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