Given that triangle RSP is a right triangle, then using the Pythagorean Theorem, RP = 5. (3²+4²=5²)
Plugging the 5 in to triangle RPQ, we find that the Theorem still works for that one, which means it is a right triangle (5²+12²=13²)
Step-by-step explanation:
Given that triangle RSP is a right triangle, then using the Pythagorean Theorem, RP = 5. (3²+4²=5²)
Plugging the 5 in to triangle RPQ, we find that the Theorem still works for that one, which means it is a right triangle (5²+12²=13²)
see explanation
Step-by-step explanation:
Using Pythagoras' identity in Δ PRS
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, then
PR² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )
PR = = 5
Using the converse of Pythagoras in Δ PQR
If the longest side squared is equal to the sum of the squares on the other 2 sides then the triangle is right.
QR² = 13² = 169
PR² + PQ² = 5² + 12² = 25 + 144 = 169
Thus Δ PQR is a right triangle, with right angle at P
It doesn't matter that much
Step-by-step explanation:
I know it from last year