Mathematics
22.08.2020 07:57
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faizanaj3978
faizanaj3978
4,8(73 marks)

Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph y= \frac {2}{5} x - 3 is below

y = - \frac {5}{2} x + 2

Step-by-step explanation:

Slope of the equation  y= \frac{2}{5} x -3   is  m_1 = \frac{2}{5}

Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as

m_2 = - \frac {1}{m_1}  = - \frac {5}{2}

Equation of line in point slope form is given as

y-y_1=m_2(x-x_1)

Here  (x1, y1) = (4, -8)

y+8 = - \frac{5}{2} (x-4)

Simplifying it further  

y = - \frac {5}{2} x + \frac {5}{2} 4 - 8

y = - \frac {5}{2} x + 2

abecobos37
abecobos37
4,6(100 marks)
That means u wouldn't have to pay 35/100 

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