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Peter buys a bag of 21 sweets. in the bag there 13 red sweets, 6 green sweets and
Peter buys a bag of 21 sweets. in the bag there 13 red sweets, 6 green sweets and 2 yellow sweets peter likes red sweets and eats 3 of them he then asks his sister to choose one sweet at random from the bag. there are 2 questions to answer. what is the probability that she chooses a red sweet? what is the probability that she chooses an orange sweet?
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Probability=number of specific outcomes/total number of outcomes...
Since Peter eats 3 reds there are only 10 reds and 18 total sweets left, therefore the probability of his sister picking a red randomly is:
10/18=5/9
There are no orange sweets so the probability of picking one is zero.
7/(b-36)=28/b
28b-1008=7b
21b=1008
b=48
a/72=28/b
a=72x28/48
a=42