Out of 136 students in a school, 60 take french, 100 take chemistry and 48 take

20

Step-by-step explanation:

Let us see the formula to find intersection of 3 sets.

n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(B∩C)-n(C∩A)+n(A∩B∩C)

Here we are given three sets as the number of students in class of French , physics and Chemistry . Let these sets be denoted by F,C, P. Hence the formula for them will be

n(F∪C∪P)=n(F)+n(C)+n(P)-n(F∩C)-n(C∩P)-n(P∩F)+n(F∩C∩P)

Also we are given that

n(F∪C∪P)=136

n(F)=60

n(C)=100

n(P)=48

n(F∩C)=28

n(C∩P)=44

n(P∩F)=20

n(F∩C∩P)=x

Hence put these values in the above equation and solve for x

136=60+100+48-28-44-20+x

136=208-92+x

136=116+x

20=x

Hence , there are 20 students who took all the three subjects.

17/20x + 7/10 = y

Step-by-step explanation:

You can solve this equation by moving values until they fit the form y=mx+b (slope-intercept form).

Hope this helps!!