Physics
13.08.2020 22:48
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Objects with masses of 130 kg and a 430 kg are separated by 0.300 m.(a) find the

Objects with masses of 130 kg and a 430 kg are separated by 0.300 m.(a) find the net gravitational force exerted by these objects on a 35.0 kg object placed midway between them.(b) at what position (other than infinitely remote ones) can the 35.0 kg object be placed so as to experience a net force of zero?
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mckinleesmomp6qj1e
mckinleesmomp6qj1e
5,0(68 marks)

Answer

given,

mass of object

m₁ = 130 Kg

m₂ = 430 Kg

distance between them = 0.3 m

a) net force when 35 kg is place in between them

   F = \dfrac{GMm}{R^2}

now,

   F = - \dfrac{6.67 \times 10^{-11}\times 130 \times 30}{0.15^2} +\dfrac{6.67 \times 10^{-11}\times 430 \times 30}{0.15^2}

   F = 3.12 \times 10^{-5}\ N

   Direction of force will be toward the mass of 430 Kg

b) position where force will be zero

 F =-\dfrac{6.67 \times 10^{-11}\times 130 \times 30}{(0.3-x)^2} +\dfrac{6.67 \times 10^{-11}\times 430 \times 30}{x^2} = 0

 -\dfrac{130}{(0.3-x)^2} +\dfrac{430}{x^2} = 0

 x^2- 0.6 x + 0.09=\dfrac{130}{430}x^2

 0.7 x^2- 0.6 x + 0.09 =0

solving the above equation

  x = 0.1936 m

the distance of third mass will be at x = 0.1936 m from 430 Kg mass.

xeskimopie
xeskimopie
4,5(50 marks)
I am not so sure about this it is too difficult

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