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01.04.2021 05:37
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NewTech Incorporated management plans on paying the company s first dividend of

NewTech Incorporated management plans on paying the company's first dividend of $2.00 three years from today (D3 = $2.00) on its' common stock. After year three the dividend is expected to grow at a constant rate of 5% thereafter. As an investor with a required rate of return of 15%, what would you pay for NewTech common stock today?
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ninaaforever
ninaaforever
5,0(63 marks)

Stock price today = $13.807

Explanation:

According to the dividend valuation model , the current price of a stock is the present value of the expected future dividends discounted at the required rate of return

This principle can be applied as follows:

The value of cash flow the stock today is the present value of the future cash flow discounted at the required rate of return

Step 1 : Compute the PV in year 3 of future dividend

PV = D× (1+g)/r-g

D- div in year 3, g- growth rate, r-required rate of return

PV in year 3 = 2× (1.05)/0.15-0.05

                   = 21

Step 2: PV in year in year 0

PV = PV in year 3 × (1+r)^(-n)

r-rate of return- 15%, n- number of years- 3

    =  21 × 1.15^(-3)

    =13.80784088

Stock price today = $13.807

leonidas117
leonidas117
4,9(87 marks)

\begin{array}{cccccc}\text{Number of milk chocolate bars}&0&1&2&3&4\\ \\\text{Probabilities}&0.0256&0.1536&0.3456&0.3456&0.1296\end{array}

Step-by-step explanation:

There are 10 chocolate bars in the box, 6 of them are milk chocolate bars. So the probability of chosing milk chocolate bar is p=\frac{6}{10}=0.6 and the probability of chosing not milk chocolate bar is q=\frac{10-6}{10}=0.4.

Chosing 4 chocolate bars, you can choose 0, 1, 2, 3, 4 milk chocolate bars. Find probabilities:

P(\text{Number of milk chocolate bars}=0)=C^{4}_0p^0q^4=1\cdot 0.6^0\cdot 0.4^4=0.4^4=0.0256

P(\text{Number of milk chocolate bars}=1)=C^{4}_1p^1q^3=4\cdot 0.6^1\cdot 0.4^3=4\cdot 0.6\cdot 0.064=0.1536

P(\text{Number of milk chocolate bars}=2)=C^{4}_2p^2q^2=6\cdot 0.6^2\cdot 0.4^2=6\cdot 0.36\cdot 0.16=0.3456

P(\text{Number of milk chocolate bars}=3)=C^{4}_3p^3q^1=4\cdot 0.6^3\cdot 0.4^1=4\cdot 0.216\cdot 0.4=0.3456

P(\text{Number of milk chocolate bars}=4)=C^{4}_4p^4q^0=1\cdot 0.6^4\cdot 0.4^0=1\cdot 0.1296\cdot 1=0.1296

So, a probability distribution table is

\begin{array}{cccccc}\text{Number of milk chocolate bars}&0&1&2&3&4\\ \\\text{Probabilities}&0.0256&0.1536&0.3456&0.3456&0.1296\end{array}

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