Methanol (ch3oh) burns according to the equation 2ch3oh(l) + 3o2(g) → 2co2(g) +
Methanol (ch3oh) burns according to the equation 2ch3oh(l) + 3o2(g) → 2co2(g) + 4h2o(l), δh°rxn = –1454 kj/mol. how much heat, in kilojoules, is given off when 75.0 g of methanol is burned?
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