Mathematics
28.06.2021 13:16
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Luke was born on October 1, 2009. His grandparents put $20,000 into an account that

Luke was born on October 1, 2009. His grandparents put $20,000 into an account that yielded 3% interest compounded quarterly . When Luke turns 17, his grandparents will give him the money for a college education . How much will Luke get on his 17th birthday ?
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marykayy0218own5cp
marykayy0218own5cp
5,0(58 marks)

30,200$

Step-by-step explanation:

3 times 17 is 51 which is interesting and 1.51 times 20,000 is 30,200$.

1930isainunez
1930isainunez
4,7(47 marks)

I suppose you're supposed to prove that set intersection is distributive across a union,

A\cap(B\cup C)=(A\cap B)\cup(A\cap C)

Two sets are equal if they are subsets of one another. To prove a set X is a subset of another set Y, you have to show that any element x\in X also belongs to Y.

Let x\in A\cap(B\cup C). By definition of intersection, both x\in A and x\in B\cup C. By definition of union, either x\in B or x\in C. If x\in B, then clearly x\in A\cap B; if x\in C, then x\in A\cap C. Either way, x\in(A\cap B)\cup(A\cap C). Hence A\cap(B\cup C)\subseteq(A\cap B)\cup(B\cap C).

The proof in the other direction uses the same sort of reasoning. Let x\in(A\cap B)\cup(A\cap C). Then either x\in A\cap B or x\in A\cap C. If x\in A\cap B, then both x\in A and x\in B; if x\in A\cap C, then both x\in A and x\in C. So certainly x\in A, and either x\in B or x\in C so that x\in B\cup C. Hence (A\cap B)\cup(A\cap C)\subseteq A\cap(B\cup C).

Both sets are subsets of one another, so they are equal.

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