Let u be an angle in the 4th quadrant with cos u=8/9 then sin u=

To solve for the last side of the triangle, use the Pythagorean Theorem:
(8)^2 + x^2 = (9)^2
x = sqrt of 17
However, this is a NEGATIVE sqrt 17 because the terminal side is in quadrant 4, meaning that this side is under the X-axis and therefore negative.
Now that you know the side opposite of u in the triangle, do opposite/hypotenuse.
sin u = -(sqrt 17)/9

In a classroom, there are 3 girls for every 7 boys. write a ratio comparing the students. 

Hope this helps