Is it possible to transfer heat from a cold reservoir to a hot reservoir? is it

Yes, if work is done, this transfer process can take place

Explanation:

The word heat means "thermal energy". If an object or body has a lot of heat, then it has a high thermal energy. If a body is cold, then it has low thermal energy, or it has a lack of thermal energy.

The reason it is not possible to transfer heat naturally from a cold object to a hot object is because there is a higher thermal energy in the hot object, and under natural circumstances thermal energy wants to move from high to low, meaning that a hot object naturally would give its thermal energy to the environment in order to then have the same amount as the environment, the same as how a cold object will absorb heat from the environment to have the same amount of thermal energy.

Hence, unless work is done, there it is not possible to transfer thermal energy from a cold object to a hot object.

a) 0.714g of bicarbonate of soda are required.

b) 0.221g of Al(OH)₃ are required

Explanation:

The reactions of HCl with bicarbonate of soda and aluminium hydroxide are:

HCl + NaHCO₃ → H₂O + NaCl + CO₂

3 HCl + Al(OH)₃ → 3H₂O + AlCl₃

The moles of HCl that we need neutralize are:

50mL = 0.050L * (0.17mol / L) = 0.0085 moles HCl

To solve these problem we need to find the moles of the antacid using the chemical reaction and its mass using its molar mass;

a) Moles NaHCO₃ = Moles HCl = 0.0085 moles

The mass is -Molar mass NaHCO₃: -84g/mol-

0.0085 moles * (84g / mol) = 0.714g of bicarbonate of soda are required

b) 0.0085 moles HCl * (1mol Al(OH)₃ / 3mol HCl) = 2.83x10⁻³ moles Al(OH)₃

The mass is -Molar mass: 78g/mol-:

2.83x10⁻³ moles Al(OH)₃ * (78g/mol) =