Physics
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In a ride in an amusement park, a carriage of mass 450 kg is travelling horizontally

In a ride in an amusement park, a carriage of mass 450 kg is travelling horizontally at a speed of 18 m/s. It passes through a shallow tank containing stationary water. The tank is of length 9.3 m. The carriage leaves the tank at a speed of 13 m/s. PT 3 a.) Calculate the change in kinetic energy of the cart while it passes through the water tank J (Hint: Change
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ashleymarie11142
ashleymarie11142
4,4(46 marks)

98.

Explanation:

divide

allie2290
allie2290
4,7(50 marks)

Average = a + b + c + d ... / # of values

70 km/h = 50 km/h + x / 2

140 km/h = 50 km/h + x

90 km/h = x

Therefore, the train would have to travel 90 km/h the second half of its journey. The standard average formula I used to solve this ONLY works when you're dealing with equal weights (Each of the two parts of the journal is 50%). If you are faced with a problem in which the parts of the journey are not equal, you will have to use the formula for weighted average, which would be:

Average = x₁y₁ + x₂y₂ + x₃y₃ + ...

In which x = value and y = relative weight (percentage -> decimal)

You can still use this formula to solve your problem.

70 km/h = (50km/h)(0.50)+ x(0.50)

140 km/h = 50 km/h + x

90 km/h = x

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