In a constant‑pressure calorimeter, 70.0 mL of 0.350 M Ba(OH)2 was added to 70.0

The amount of heat absorbed by the solution is 2.795 kJ

Explanation:

To calculate the mass of water, we use the equation:

Density of water = 1 g/mL

Volume of water = [70 + 70] = 140 mL

Putting values in above equation, we get:

To calculate the heat absorbed, we use the equation:

where,

q = heat absorbed

m = mass of water = 140 g

c = heat capacity of water = 4.186 J/g°C

= change in temperature =

Putting values in above equation, we get:

Hence, the amount of heat absorbed by the solution is 2.795 kJ

carbon tetrafluoride tetra fluoromethane

Explanation: