The coordinates of the location of point B are (0 , 3) ⇒ answer A
Step-by-step explanation:
* Lets revise some facts
- In the square the diagonals bisect each other, that means they meet
each other at their mid-point
- In square ABCD , AC and BD are its diagonal
- AC and DB intersect each other at point M where M is the midpoint of
AC and BD
- The rule of the midpoint of the line whose endpoints are (x1 , y1) and
(x2 , y2) is
∵ A = (-2 , 4) and C = (-1 , 1)
∵ M is the mid-point of AC
∴
- M is also the mid point of BD
∵ D = (-3 , 2) and M = (-1.5 , 2.5)
- Let B = (x , y)
∵ -1.5 = (x + -3)/2 ⇒ multiply both sides by 2
∴ -3 = x + - 3 add 3 to both sides
∴ 0 = x
∴ The x-coordinate of B is 0
∵ 2.5 = (y + 2)/2 ⇒ multiply both sides by 2
∴ 5 = y + 2 subtract 2 from both sides
∴ 3 = y
∴ The y-coordinate of B is 3
∴ B = (0 , 3)
* The coordinates of the location of point B are (0 , 3)