The magnitude of the object's acceleration is 4.72 m/s².
The given parameters;
mass of the object, m = 2 kgfirst force on the object, F1 = (3i - 8j) Nsecond force on the object, F2 = (5i +3j)The net force on the object is calculated as follows;
The resultant force on the object is calculated as follows;
The magnitude of the object's acceleration is calculated by applying Newton's second law of motion;
Thus, the magnitude of the object's acceleration is 4.72 m/s².
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4.7m/s²
Explanation:
According to newton's first law,
Force = mass × acceleration
Since we are given more the one force, we will take the resultant of the two vectors.
Mass = 2.0kg
F1+F2 = (3i-8j)+(5i+3j)
Adding component wise, we have;
F1+F2 = 3i+5i-8j+3j
F1+F2 = 8i-5j
Resultant of the sum of the forces will be;
R² = (8i)²+(-5j)²
Since i.i = j.j = 1
R² = 8²+5²
R² = 64+25
R² = 89
R = √89
R = 9.4N
Our resultant force = 9.4N
Substituting in the formula
F = ma
9.4 = 2a
a = 9.4/2
a = 4.7m/s²
Therefore, magnitude of the acceleration of the particle is 4.7m/s²
yoy
Explanation: