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12.08.2021 01:54
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If 30.0 ml of ca(oh)2 with an unknown concentration is neutralized by 40.0 ml of

If 30.0 ml of ca(oh)2 with an unknown concentration is neutralized by 40.0 ml of 0.175 m hcl, what is the concentration of the ca(oh)2 solution? show all of the work needed to solve this problem. (2 points) ca(oh)2 + 2hcl yields 2h2 o + cacl2
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kush3489t
kush3489t
4,6(29 marks)

Concentration of Ca(OH)β‚‚:

0.117 M.

Explanation:

How many moles of HCl is consumed?

Note the unit of concentration: moles per liter solution.

c(\text{HCl}) = 0.175\;\text{M} = 0.175\;\text{mol}\cdot\textbf{L}^{-1}.

Convert milliliters to liters.

V(\text{HCl})=40.0\;\text{mL} = 0.0400\;\text{L}.

n(\text{HCl}) = c(\text{HCl})\cdot V(\text{HCl})= 0.175\;\text{mol}\cdot\text{L}^{-1} \times 0.0400\;\text{L}= 7.00\times 10^{-3}\;\text{mol}.

How many moles of NaOH in the solution?

Refer to the equation. The coefficient in front of Ca(OH)β‚‚ is 1. The coefficient in front of HCl is 2. In other words, it takes two moles of HCl to neutralize one mole of Ca(OH)β‚‚. That 7.00\times 10^{-3}\;\text{mol} of HCl will neutralize only half that much Ca(OH)β‚‚.

\displaystyle n(\text{Ca}(\text{OH})_2)=\frac{1}{2}\;n(\text{HCl}) = 3.50\times 10^{-3}\;\text{mol}.

What's the concentration of the Ca(OH)β‚‚ solution?

Concentration is the number of moles of solute per unit volume.

\displaystyle c(\text{Ca}(\text{OH})_2) = \frac{n(\text{Ca}(\text{OH})_2)}{V(\text{Ca}(\text{OH})_2)} = \frac{3.50\times 10^{-3}\;\text{mol}}{0.0300\;\text{L}}=0.117\;\text{mol}\cdot\text{L}^{-1}.

sukhmanksidhu
sukhmanksidhu
4,9(50 marks)

PVC is made by the polymerisation of vinyl chloride (chloroethene)

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