I m pretty sure they re congruent according to the sas postulate but could someone

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Step-by-step explanation:

I find it easiest to do this by synthetic division.

The zero of the divisor binomial is put in the tableau at upper left, and the coefficients of the dividend polynomial are listed across the top. The leftmost dividend coefficient (8) is brought down, and the multiplication and addition proceed left-to-right according to the instructions in the attached figure.

The final sum is the remainder. Here, it is 132, so the dividend polynomial is not evenly divisible by (x -4).