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We know that resistance of the wire is directly proportional to length and inversely proportional to area. So the resistance would be 16 times the original resistance (4 times 4). If “R” was the original resistance of the wire, then the new resistance would be “16 R”.
Explanation:
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Featured snippet from the web
We know that resistance of the wire is directly proportional to length and inversely proportional to area. So the resistance would be 16 times the original resistance (4 times 4). If “R” was the original resistance of the wire, then the new resistance would be “16 R”.
Explanation:
Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson, and you should commit these equations to memory):
s = ut + ½ at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity v is final velocity a is acceleration and t is time.
In this case, we have u = 26m/s, a = 7m/s^2, t = 25sec, and we want to know the distance, s
So we choose equation (1) s = ut + ½ at^2
s = 26(25) + ½(7)(25^2)
s = 650 + 2187.5
s = 2837.5m
The total distance covered is 2837.5m