Computers and Technology
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How many permutations for a 7 characters in length string, which contains all following

How many permutations for a 7 characters in length string, which contains all following letters R, X, S, Y, T, Z, U, has either the string 'RXS' or string 'ZU' in the 7 characters string?
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ceburns23
ceburns23
4,7(17 marks)

Following are the solution to this question:

Explanation:

In the following forms, RXS can appear:  

R X S \_ \_ \_  \_ it may look like that really, 4 \times 3  \times 2  \times 1 forms = 24 may construct the remainder of its letters.  

\_ R X S  \_ \_  \_ it may look like that really,  4 \times 3  \times 2  \times 1 forms = 24 may construct the remainder of its letters.  

\_  \_  R X S \_  \_ it may look like that really, 4 \times 3  \times 2  \times 1 forms = 24 may construct the remainder of its letters.  

\_ \_ \_  R X S \_ it may look like that really,  4 \times 3  \times 2  \times 1 forms = 24 may construct the remainder of its letters.  

\_ \_ \_ \_ R X S it may look like that really,  4 \times 3  \times 2  \times 1 forms = 24 may construct the remainder of its letters.  

And we'll have a total of 24 \times 5 = 120 permutations with both the string RXS.

In the following forms, UZ can appear:

U Z \_ \_ \_ \_\ _  They can organize your remaining 5 characters through 5 categories! Procedures = 5 \times 4 \times  3 \times 2 \times 1 = 120

\_ UZ \_ \_ \_ \_ They can organize your remaining 5 characters through 5 categories! Procedures = 5 \times 4 \times  3 \times 2 \times 1 = 120

\_ \_ U Z \_ \_ \_They can organize your remaining 5 characters through 5 categories! Procedures  = 5 \times 4 \times  3 \times 2 \times 1 = 120

\_ \_ \_ U Z \_ \_They can organize your remaining 5 characters through 5 categories! Procedures  = 5 \times 4 \times  3 \times 2 \times 1 = 120

\_ \_ \_ \_ U Z  \_ They can organize your remaining 5 characters through 5 categories! Procedures  = 5 \times 4 \times  3 \times 2 \times 1 = 120

\_ \_ \_  \_ \_ U Z They can organize your remaining 5 characters through 5 categories! Procedures  = 5 \times 4 \times  3 \times 2 \times 1 = 120

There may be 120 \times 6 = 720 ways of complete permutations.

ahankaranth
ahankaranth
4,6(67 marks)

wa is this for?

Explanation:

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