How many grams of C2H5OH are used up when 6.25 grams of O2 react according to the

Hello,

I believe this is (25 g Al) * (1 mol H / 1.008 g H) = 24.8015 mol H

Hopefully that was the right approach.
I thought that if one mole of Al is
26.982 g, then the numbers of moles for H (1.008 g/mol) would be about 25 mol.
If it doesn’t make sense or if you have resources/notes to which I can refer, I’ll see what I can do!

Good luck!